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  • (a) Two electric field lines cannot cross each other. Also, they cannot form closed loops. Give reasons. (b) A particle of charge and mass 1·6 g is movi

(a) Two electric field lines cannot cross each other. Also, they cannot form closed loops. Give reasons.

(b) A particle of charge 2 \mu Cand mass 1·6 g is moving with a velocity 4 \widehat{i} ms^{-1}. At t = 0 the particle enters in a region having an electric field \overrightarrow{E} (in NC^{-1} ) = 80 \widehat{i} + 60 \widehat{j} . Find the velocity of the particle at t = 5 s.

 

 

 
 
 
 
 

Answers (1)

i) A tangent drawn at any point on a field line gives the direction of force experienced by a unit positive charge due to the electric field on that point. If two lines intersect at a point, then the tangent drawn there will give two directions of force, which is not possible. Hence two field lines cannot cross each other at any point.

ii) Since the electric field lines start from positive charge and terminate at the negative charge hence closed loops are not possible.

b)

\\a=\frac{qE}{m}=\frac{2\times10^{-6}(80i+60j)}{1.6\times10^{-3}}\\\\=(10i+7.5j)\times10^{-2}m/s^2

\\v=u+at\\v=4i+(0.1i+.075j)\times5\\v=4.5i+.375j

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Safeer PP

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