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A Unit vector perpendicular to both i+j+k and 2i+j+3k is

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Solution:  A vector  Perpendicular to the two given vectors

 veca  and  vecb will be some scalar multiple of  veca	imes vecb.

Now ,        veca	imes vecb=eginvmatrix i &j &k \ 1 &1 & 1\ 2 &1 &3 endvmatrix=i(3-1)-j(2-3)+k(1-2)

veca	imes vecb=2i-j-kRightarrow left | 2i-j-k 
ight |=sqrt6

Thus             frac(2i-j-k)sqrt6   is such a unit vector.

Posted by

Deependra Verma

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