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(a)    Using valence bond theory, write the hybridisation and magnetic character of the complex[Fe(CN)_6]^{4-}. Atomic Number of Fe = 26)

(b)    Write the electronic configuration of d 6 on the basis of crystal field theory when

  1. \Delta_0<P and
  2. \Delta_0>P

 

 

 

 
 
 
 
 

Answers (1)

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(a)

\\Fe = 3d^64s^2\\Fe ^{+2} = 3d^64s^0

CN- being a strong ligand, par up the electron & we get 

Hybridization = d^2sp^3

Since there are no unpaired electrons, it is diamagnetic.

(b)   

(1)  

 

(2)    

\Delta_0 > P

                d^6 = t^6_{2g}e^0g   

Posted by

Sumit Saini

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