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A wire AB is carrying a current of 12 A and is lying on the table. Another wire CD, carrying a current of 5 A is arranged just above AB at a height of 1 mm. What should be the weight per unit length of this wire so that CD remains suspended at its position? Indicate the direction of current in CD.
Answers (1)
Weight of the wire will be balanced by the force of repulsion between the wires AB and CD so that the wire CD remains suspended at it's position.
The direction of current in CD will be opposite to that of in AB.
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