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ABCD is a trapezium in which AB is parallel to DC . P and Q are points on sides AD and BC such that PQ is parallel to AB .if PD=18,BQ=35, and QC=15,then find AD.

Answers (1)

D Deependra Verma

$In; riangle ABD,\* PO||AB;;;;;;;;;;;;;;;;;;;;;;[ecause PQ||AB ]\* Rightarrow By;basic;proportionality;theorem\* Rightarrow fracDPAP=fracDOOB;;;;;;;;;;;;;........eq(1)\* In; riangle BDC,\* PO||AB;;;;;;;;;;;;;;;;;;;;;;;;[ecause PQ||DC]\* Rightarrow By;basic;proportionality;theorem\* Rightarrow fracBQQC=fracDOOB;;;;;;;;;;;;;........eq(2)\*From;eq(1);and;eq(2)\*Rightarrow fracDPAP=fracQCBQ\*Rightarrow frac18AP=frac1535\* Rightarrow AP=42\* herefore AD=AP+PD=42+18=60;cm\*Rightarrow AD=60;cm$

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