Get Answers to all your Questions

header-bg qa

Amit, standing on a horizontal plane, finds a bird flying at a distance of 200 m from him at an elevation of 30o. Deepak standing on the roof of a 50 m high building, finds the angle of elevation of the same bird to be 45o. Amit and Deepak are on opposite sides of the bird. Find the distance of the bird from Deepak.

 

 

 
 
 
 
 

Answers (2)

Given in the question,

Bird flying at a distance of 200m from Amit at an elevation of 30\degree.

So, In \Delta APQ

    \sin 30 = \frac{PQ}{AP}

    \frac{1}{2} = \frac{PQ}{AP}

    PQ = \frac{AP}{2} = \frac{200}{2} = 100 m

PQ = PR + RQ

100 =PR + PQ \Rightarrow PR = 50 m

In \Delta PRD

\sin 45 = \frac{PR}{PD}

\frac{1}{\sqrt2} = \frac{PR}{PD}

PD = 50\sqrt{2} \ m

Distance of bord from Deepak is 50\sqrt2 \ m

Posted by

Safeer PP

View full answer

247.48

 

Posted by

Manisha rajput

View full answer