Among all the isomers of molecular formula $C_4H_9Br,$ identify (a) the one isomer which is optically active.(b) the one isomer which is highly reactive towards $S_N2.$(c) the two isomers which give same product on dehydrohalogenation with alcoholic $KOH$.

Answers (1)

(a) $2-Bromobutane$

(b) $CH_3CH_2CH_2CH_2Br$ is highly reactive towards $SN^2$ as it is a primary halide.

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