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An AP consists of 50 terms of which the 3rd term is 12 and the last term is 106.Find the 29th term.​

Answers (1)

Assume first term of A.P. is a , it's common difference is d.

Given :

T(3 ) = a + 2d = 12 ...(i)

T(50) = a + 49d = 106....(ii)

Equation (ii) - Equation (i)

a + 49d -a - 2d = 106 -12

47d = 94

d =2

a = 8

29th Term T(29) = a + 28d 

                           = 8 + 28x2

                           = 64

 

Posted by

Ravindra Pindel

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