Assume first term of A.P. is a , it's common difference is d.
Given :
T(3 ) = a + 2d = 12 ...(i)
T(50) = a + 49d = 106....(ii)
Equation (ii) - Equation (i)
a + 49d -a - 2d = 106 -12
47d = 94
d =2
a = 8
29th Term T(29) = a + 28d
= 8 + 28x2
= 64