An electric lamp of 100 ?, a toaster of resistance 50 ?, and a water filter of resistance 500 ? are connected in parallel to a 220 V source.

Answers (1)

Given : R_1=100Omega ,R_2=50Omega ,R_3=500Omega

    R=Equivalent  resistance

    frac1R=frac1R_1+frac1R_2+frac1R_3 

Rightarrow frac1R=frac1100+frac150+frac1500

Rightarrow frac1R=frac5+10+1500=frac16500

Rightarrow R=frac50016=31.25Omega

By Ohm's law,

                   I=fracVR=frac22031.25=7.04A

Hence, the resistance of electric iron is 31.25 and current through it is 7.04A.

 

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