General electronic configuration of outermost and penultimate shell of an atom is (n-1)s^{2} (n-1)p^{6} (n -1)d^{x} ns^{2} . If n=4  the number of proton in the nucleus is

Answers (1)

Substituting the values, we get the configuration to be $[N e] 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{5}$ 
The atomic number is 10+2+6+2+5=25
Number of proton = Atomic number
Therefore, the number of protons in the nucleus is 25.

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