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Answer the following:

(a) What is the general electronic configuration of lanthanoids?

(b) What are the common oxidation states of Cerium (At.no. 58)?

(c) Why do actinoids show a wide range of osidation states?

 

 

 

 
 
 
 
 

Answers (1)

(a) General electronic configuration of lanthnaoids is \left [Xe \right ] 4f ^{1-14}5d^{0-1}6s^{2}

(b) The common oxidation state of cerium is +3 and +4.

(C) Actinoids shows a wide range of oxidation state due to low energy gap between 4f, 5d and 6s orbitals.

Posted by

Sumit Saini

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