# Arrange the hydrides of group 16 in order of increasing boiling points, giving reason. Name the hydride which is most stable thermodynamically.

→ $H_{2}O$ show hydrogen bonding due to high electronegativity of oxygen.

→  As we go down the group, the size of atom increases and hence the strength of Van der Waal's force increases. Thus, the boiling point increases down the group.

→ Hence, increasing order of boiling point is,

$H_{2}S < H_{2}Se

→  Shorter is the hydride bond, larger is the stability. Hence, $H_{2}O$ is the most stable thermodynamically.

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