Arrange the hydrides of group 16 in order of increasing boiling points, giving reason. Name the hydride which is most stable thermodynamically.

 

 

 

 
 
 
 
 

Answers (1)
S Sumit

→ H_{2}O show hydrogen bonding due to high electronegativity of oxygen.

→  As we go down the group, the size of atom increases and hence the strength of Van der Waal's force increases. Thus, the boiling point increases down the group.

→ Hence, increasing order of boiling point is,

        H_{2}S < H_{2}Se<H_{2}Te<H_{2}O

→  Shorter is the hydride bond, larger is the stability. Hence, H_{2}O is the most stable thermodynamically.

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