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Asif has 4 times as many one rupees coins as he has five rupees coins.if he had a total of 81 rupees then find the denominator of one rupees coin he has?

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Given that,  Asif has 36 one rupee coins.

Let the number of 5 rupee coins be x.

Number of 1 rupee coins = 4x

So,

Amount of 5 rupee coins = 5x

Amount of 1 rupee coin = 4x

Total amount = Rs.81

Hence accordpng to question,

5x + 4x = 81

9x = 81

x = 9

Hence, number of 5 rupee coins = 9

Number of 1 rupee coins = 36

Posted by

himanshu.meshram

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