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At Residential area Sector 22 if 500 characters were burnt to produce 80 DB of noise pollution how many crackers they should burst so that only 5 DB of noise pollution is created​

Answers (1)

500 produce 80

so 1 DB is produced by 500/80 = 25/4

Therefore  5 DB is produced by

125/4 characters. Approximately  31

 

 

Posted by

Safeer PP

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