# Bag I contains 3 red and 4 black balls and Bag II contains 4 red and 5 black balls.One ball is transferred from Bag I to Bag II and then two balls are drawn atrandom (without replacement) from Bag II. The balls so drawn are found to beboth red in colour. Find the probability that the transferred ball is red.

Let the event of drawing a red ball frm bag 2 be p(A)
p(A)=4/10,
let event of drawing second red ball frm bag 2 is p(B/A)
p(B/A)=3/9
so,the probability of drawing two red balls frm bag 2 is
p(AÐ¿B)=(4/10)*(3/9)=12/90

### Preparation Products

##### JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
##### Rank Booster NEET 2021

This course will help student to be better prepared and study in the right direction for NEET..

₹ 13999/- ₹ 9999/-
##### Knockout JEE Main April 2021 (Easy Installments)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
##### Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-