#### By using the concept of equation of a line, prove that the three points (3,0), (-2, -2) and (8, 2) are collinear.

$In\;order\;to\;show\;that\;the\;points\;(3,0),\;(-2,-2)\;and\;(8,2)\;are\\* collinear,\;it\;suffices\;to\;show\;that\;the\;line\;passing\;through\;point\\* (3,0)\;and\;(-2,-2)\;also\;passes\;through\;point\;(8,2).\\*The\;equation \;of\; the\;line\;passing\;through\;points\;(3,0),\;(-2,-2)\;is\\*\Rightarrow y-0=\frac{-2-0}{-2-3}(x-3)\\*\Rightarrow 5y=2x-6\\* i.e.\;2x-5y=6\\* It\;is\;observed\;that\;at\;x=8\;and\;y=2,\\*L.H.S.=2\times8-5\times2=16-10=6=R.H.S.\\*Therefore,\;the\;line\;passing\;through\;points\;(3,0)\;and\;(-2,-2)\\*also\;passes\;through\;point\;(8,2).\\*Hence,\;points\\* (3,0),\;(-2,-2)\;and\;(8,2)\;are\;collinear.$