Calculate the final velocity when a body moves from rest & attains an acceleration of 5m/sec² covering a distance of 50 meters

Answers (1)

Initially body is at rest , hence initial velocity is Zero .
Acceleration = 5 m /s^2
Distance traveled =  50 meters.
We Know that
   V² - U² = 2as
Where V = final velocity  ,
U = initial velocity 
a = Acceleration of the body
s= Distance Covered

V² - 0² = 2*5*50
 V² = 500
V = √(500)
V = 10√5
Hence the Final Velocity of the body is 10√5.

 

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