Calculate the number of different ways in which six-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5: a) Without repetition, assuming that a number cannot begin with 0 b) With repetition, assuming a number cannot begin with 0

Answers (1)

a)  Number of different ways in which six-digit numbers can be form without repetation = 5x5x4x3x2x1= 600

b) Number of different ways in which six-digit numbers can be form with repetation = 5x6x6x6x6x6= 38880

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