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  • Campie Anght triangle, whose base and height are 15 cm. and 20 cm, respectivesmade to revolve about its hypotenuse. Find the volume and surface area of the double conformed (Use =3.14).?

Campie Anght triangle, whose base and height are 15 cm. and 20 cm, respectivesmade to revolve about its hypotenuse. Find the volume and surface area of the double conformed (Use =3.14).?

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On;rotating;about;AB;it;will;form;a;shape;with;two;cones.\* Now;In; riangle ABC,\* AC^2=AB^2+BC^2\*AC= sqrt225+400 =25 \* So,;CD=AC-AD=25-AD\* In,; riangle ABD\* AB^2=AD^2-BD^2\* Rightarrow BD^2=225-AD^2;;;;;;...eq(1)\* In,; riangle BDC\* BC^2=CD^2+BD^2\*BD^2=400-CD^2 ;;;;;;...eq(2) \* from;eq(1);and;eq(2)\* 225-AD^2=400-CD^2\* Rightarrow 175=625+ AD^2-50AD+AD^2\* Rightarrow AD=frac45050=9\*Rightarrow AD=9;cm\* Rightarrow CD=25-9=16;cm\* BD=sqrt225-81=12;cm\* Now,;volume;of;cone= frac13pi r^2 h\* total;surface;area;of;cone =pi r(r+l)\* Now,\* volume;of;upper;cone=frac13pi (12)^2 9= 1357.16;cm^3\* total;surface;area;of;upper;cone=pi (12)(12+15)= 1017.88;cm^2\* volume;of;lower;cone= frac13pi (12)^2 16= 2412.74;cm^3\* Total;surface;area;of;the;lower;cone=pi (12)(12+20) ;=1206.37;cm^2\*Now,\*Total;volume=1357.16+2412.74=3769.9;cm^3\* Total;surface;area=1017.88+1206.37=2224.25;cm^2

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Deependra Verma

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