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Check whether the sequence 5, 5.4, 5.8, 6.2, 6.6, ... is an A.P. If yes, find the common difference.

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To be an A.P., the difference between consecutive terms must be constant. Given here;

First term $a_1=5$
Second term $a_2=5.4$
Third term $a_3=5.8$
Fourth term $a_4=6.2$
Fifth term $a_5=6.6$

Now, calculate the common differences (d):
$$
\begin{aligned}
& d_1=a_2-a_1=5.4-5=0.4 \\
& d_2=a_3-a_2=5.8-5.4=0.4 \\
& d_3=a_4-a_3=6.2-5.8=0.4 \\
& d_4=a_5-a_4=6.6-6.2=0.4
\end{aligned}
$$

As the common difference d = 0.4 is the same for all terms, the given sequence is an A.P.

Posted by

Saniya Khatri

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