Check whether the sequence 5, 5.4, 5.8, 6.2, 6.6, ... is an A.P. If yes, find the common difference.
To be an A.P., the difference between consecutive terms must be constant. Given here;
First term $a_1=5$
Second term $a_2=5.4$
Third term $a_3=5.8$
Fourth term $a_4=6.2$
Fifth term $a_5=6.6$
Now, calculate the common differences (d):
$$
\begin{aligned}
& d_1=a_2-a_1=5.4-5=0.4 \\
& d_2=a_3-a_2=5.8-5.4=0.4 \\
& d_3=a_4-a_3=6.2-5.8=0.4 \\
& d_4=a_5-a_4=6.6-6.2=0.4
\end{aligned}
$$
As the common difference d = 0.4 is the same for all terms, the given sequence is an A.P.