Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Answers (1)

Given : potential  difference = 50 V.

                 Charge = 9600 C

                time = 1 hr=3600 s

I=fracchargetime(seconds)=frac96003600=frac803A

So,     H=VIt

       Rightarrow H=50	imes frac803	imes 3600

      Rightarrow H=4800000J=4.8	imes 10^6J

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