# Consider a battery charger that is supplying a voltage of 112 V. A cell of EMF 12 V is to be charged. Its internal resistance is 1 ohm. We have to limit the current to 5 A for a technical reason. In order to do this, how much resistance must be attached in series to the cell

Let R is the value of resistance to be connected. The current flowing through the circuit is 5A

$\\\5A=\frac{112-12}{0.5+R}\\\\5(0.5+R)=100\\\\0.5+R=20\\\\R=19.5\Omega$

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