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  • Considering only the principal values ,if tan(cos^-1x) =sin[cot^-1(1/2)]

Considering only the principal values ,if tan(cos^-1x) =sin[cot^-1(1/2)]

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Solution:    Put  cot^-1(1/2)= heta   Rightarrow   cot heta =1/2 , sin heta =2/sqrt5

                Again put cos^-1x=phi Rightarrow cosphi =x

               The given equation then reduces to anphi =2/sqrt5

              Rightarrow      x=cosphi =sqrt5/3 .

             

Posted by

Deependra Verma

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