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  • Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are of the corresponding sides of the first triangle. <

Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are \frac{3}{5} of the corresponding sides of the first triangle.

 

 

 
 
 
 
 

Answers (1)

We need to construct first a \triangle ABC with direction 5,6,7 cms
Step for Construction \rightarrow

(i) Draw a line BC = 7 cm
(ii) Taking B as centre draw an arc with radius 6 cm
(iii) Taking C as centre draw an arc with radius 5 cm
(iv) The point where the arcs intersect is the point A
(v) Join AB and AC \triangle ABC is farmed
(vi) Now take scale facter of \frac{3}{5}
(vii) Draw a ray BX making an acute angle with BC
(viii) Taking scale factor of \frac{3}{5} mark 5 equidistant points (B1,B2,B3,B4,B5) on BX having BB1=B1B2=B2B3=B3B4=B4B5
(ix)Join B5C
(x) Draw a parallel line B3C' || B5 C
(xi) Draw a parallel line from C' [A' C' || AC]
(x) \triangle {A}'B {C}' is formed which is \frac{3}{5} of \triangle AB C

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