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Construct a triangle with sides 5 cm, 6 cm and 7 cm. Now construct another triangle whose sides are \frac{2}{3} times the corresponding sides of the first triangle.

 

Answers (1)

Steps of construction are:-

(i) Firstly draw a line segment AB of length 5 cm.

(ii) Now cut an arc of radius 6 cm from point A and an arc of 7 cm from point B.

(iii) Name the point of intersection of arcs to be point C.

(iv) Now join point AC and BC. Thus \Delta ABC is the required triangle.

(v) Draw a line AD which makes an acute angle with AB and is opposite of vertex C.

(vi) Cut three equal parts of line AD namely AA , AA , AA 3 .

(vii) Now join Ato B. Draw a line A B' parallel to A B.

(viii) And then draw a line B'C' parallel to BC.

Hence \Delta AB'C' is the required triangle.

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Safeer PP

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