Get Answers to all your Questions

header-bg qa

Define self-inductance of a coil. Obtain the expression for the energy stored in an inductor L connected across a source of emf.

 

 
 
 
 

Answers (1)

Self-induction: Induction of emf in a coil due to change in current in the same coil

flux linkage

 N\phi\; \alpha \; I

        \therefore N\phi\; =LI

Where L is known as the coefficient of self-induction or self-inductance.

Consider an inductor connected across an emf E. For current I at an instant in the circuit

\frac{dw}{dt}=EI

=\frac{LdI}{dt}\times I

dw=LIdI

The amount of work done in establishing the current I is

w = \int dw=\int_{0}^{I}LIdI

  =\frac{1}{2}LI^{2}=energy\; stored

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads