# Diagonal of a rhombus is 10 cm and 24 cm if perimeter is

$\\ \text{Diagonals of the rhombus} = 10cm, 24cm \\ \text{Diagonals meet at the center and forms right angled triangles. So by using pythagoras theorem}\\ \text{length of the base} = 10/2 = 5cm \\ \text{Length of the height} = 24/2 = 12cm\\ \text{Hypotenuse}^2 = side^ 2+ side^2 =25 + 144 = 169 \\ \text{Hypotenuse} = 13 cm \\ \text{Hence the side of the rhombus is 13cm.} \\ \text{Perimeter of the rhombus} = 4\times side = 4 \times 13 = 52cm.$

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