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  • Differentiate log(secx + tanx ) with respect to x.

Differentiate log(secx + tanx ) with respect to x.

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Solution: We have , y=log(secx+tanx)  . putting u=secx+tanx   , we get 

                    y= log u     and   u= secx +tanx

herefore                 fracmathrmd ymathrmd u=frac1u      and     fracmathrmd umathrmd x= secx. tanx +sec^2x

Now  ,      fracmathrmd ymathrmd x=fracmathrmd ymathrmd u imes fracmathrmd umathrmd x

Rightarrow           fracmathrmd ymathrmd x=frac1u imes(secx . tanx +sec^2x)=frac1(secx+tanx)secx(tanx+secx)=secx   

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Deependra Verma

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