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  • Distance between point (3,-2) (7,1)  

Distance between point (3,-2) and (7,1)?

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Given - Two points be $A(3,-2)$ and $B(7,1)$

Solution- Using formula, $AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute the coordinates:  $\sqrt{(7 - 3)^2 + (1 - (-2))^2} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5$

Therefore, the distance between the two points is $5$ units.

Posted by

Saniya Khatri

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