Divide 51 into two parts such that their product is 378......................

Answers (1)

Let's assume that one number be 'k'
therefore, other number will be 51-k
(k) x (51-k)=378
51k- k2 =378

k2 - 51 k + 378= 0
k2 - 42 k -9k + 378= 0
k(k-42) -9(k-42)=0
(k-42)(k-9)=0
k-42=0  or k-9=0
 k=42  or k=9
If one number is 42, then the other numberis 9.  

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