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  • Draw an isosceles triangle ABC in which the base BC is 8 cm long and its altitude AD through A is 4 cm long. Then draw another triangle whose sides are  <img alt="\frac{2}{3}" src="https://entrancecorner.codecogs.com/gif.latex?%5Cfrac%7B2%7D%

Draw an isosceles triangle ABC in which the base BC is 8 cm long and its altitude AD through A is 4 cm long. Then draw another triangle whose sides are  \frac{2}{3}  of the corresponding sides of  \bigtriangleup ABC.

 

 
 
 
 
 

Answers (1)

To draw: isosceles  \bigtriangleup ABC with

AB=AC

BC=8\; cm

AD=4\; cm

and then draw a triangle which is  \frac{2}{3}\bigtriangleup ABC

\rightarrow Steps for construction :

(i) Draw a line BC=8\;cm

(ii) Draw a perpendicular bisector of BC which intersects BC at D.

(iii) Mark A on the bisector such that AD=4\; cm.

(iv) Join A to B and A to C.

(v) Draw a ray BX making an acute angle with the line BC. 

(vi) Take scale factor of  \frac{2}{3}.

(vii) Mark B_1,B_2,B_3  on BX such that BB_1=BB_2=BB_3

(viii) Join B_3C.

(ix) Draw  B_2C'\parallel B_3C  to meet BC at C'.

(x) From C' draw C'A'\parallel CA  to meet A'.

Hence  \bigtriangleup A'\!BC'  is the required triangle which is \frac{2}{3}\bigtriangleup ABC

 

Posted by

Safeer PP

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