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Due to heavy floods in a state, thousands were rendered homeless, 50 schools collectively offered  to the state governments to provide the place and the canvas for 1500 tents to be fixed by the government and decided to share the whole expenditure equally The lower part of each tent is cylindrical of base radius 2.8m and height 3.5, with the conical upper part of the same base radius but of height 2.1m. If the canvas used to make the tents cost 120 per sq.m, find the amount shared by each school to set up the tents. what value is generated by the above problem? 

 

 

 

 
 
 
 
 

Answers (1)

No. of tents = 1500 

radius = 2.8 m 

height of cylindrical part = H = 3.5 m

height of conical part = h = 2.1 m 

now , slant height of conical part = l = \sqrt { h^2 + r^2} \\\\ \sqrt { 2.1 ^ 2 + 2.8 ^2} \\\\ l = \sqrt { 4.41 + 7.84 } = \sqrt { 12.25 } = 3.5\\\\ l = 3.5 \\\\

surface area of tent = CSA of conical part + CSA of cylindrical part 

= \pi rl + 2 \pi r H \\\\ = \pi r ( l+ 2 H )\\\\ = 22/7 \times 2.8 ( 3.5 + 2 \times 3.5 ) \\\\ = 22/7 \times 2.8 \times 3 \times 3.5 = 92.4

The surface area of tent = 92.4m2

The surface area of 1500 tents = 1500 * 92.4m = 138600 m2

Cost of 1m2  canvas = Rs 120 

costs of 138600 m2 canvas = 120 * 138600 

costa shared by each school = 

\frac{120\times 138600}{50 }= 332,640 Rs

Cost shared by each school = Rs 332640 /- 

humanitarian and helpful nature is shown by students and teachers 

Posted by

Ravindra Pindel

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