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During a trekking activity of 3km a student Ram will go to Sangam and return back up to 12 noon. He estimates that he can go to the Sangam at 0.75km/h on average, and return at half of that speed. what is the latest time he can begin his walk so that he can return by 12 noon?​

Answers (1)

Tracking distance = 3km

Total Time taken by ram = 3/0.75 + 6x2/.75= 12 hours

Ram has returned back at 12 noon, so he should begin his walk at 12 mid night, so he return at 12 noon.    

Posted by

Ravindra Pindel

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