Evaluate :
           \int \frac{\cos 2x+2\sin ^{2}x}{\cos ^{2}x}dx

 

 

 

 
 
 
 
 

Answers (1)

\int \frac{\cos 2x+2\sin ^{2}x}{\cos ^{2}x}dx= \int \frac{\cos ^{2}x-\sin ^{2}x+2\sin ^{2}x}{\cos ^{2}x}dx
                                                                    \left [ \because \cos 2x= \cos ^{2}x-\sin ^{2}x \right ]
                                         = \int \frac{\cos ^{2}x+\sin ^{2}x}{\cos ^{2}x}dx
                                         = \int \frac{1}{\cos ^{2}x}dx= \int \sec ^{2}x\, dx
                                         =\tan x+c

Preparation Products

Knockout NEET Sept 2020

An exhaustive E-learning program for the complete preparation of NEET..

₹ 15999/- ₹ 6999/-
Buy Now
Rank Booster NEET 2020

This course will help student to be better prepared and study in the right direction for NEET..

₹ 9999/- ₹ 4999/-
Buy Now
Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
Buy Now
Test Series NEET Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 11999/-
Buy Now
Exams
Articles
Questions