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Evaluate: cos^-1(cos7pi/6)

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Solution:    cos^-1[cos(7pi/6)] eq 7pi/6 , Because 7pi/6

                  Does not lies between 0 and pi

     Now,  cos^-1[cos(7pi/6)]=cos^-1[cos(2pi-5pi/6)]

  Rightarrow            cos^-1[cos(5pi/6)]=5pi/6 

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Deependra Verma

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