Evaluate integral of x+cos 6 x/3 x²+sin 6 xplease ans with detail

Answers (1)

Intergral of fracx+cos6x3x^2+sin6x=fracuv
Taking 3x^2+sin6x=v and differentiating with respect to x
fracmathrmd vmathrmd x=6x+6cos6x
u=frac16fracmathrmd vmathrmd x
int fracx+cos6x3x^2+sin6xmathrmd x
Rightarrow frac16int frac1vmathrmd v
Rightarrow frac16log v
Rightarrow frac16log (3x^2+sin6x)
 

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