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Factorise 2y³+y²-2y-1 by using factor theorem
Answers (1)
f(y) = 2y3+y2-2y-1
Put y = 1 we get f(1) = 2+1-2-1=0
2y3+y2-2y-1 = (y-1) (2y2 -3y+1)
Put y=1 in (2y2 -3y+1) we get 2 -3+1 =0.
(y-1) is the factor of (2y2 -3y+1).
2y3+y2-2y-1 = (y-1) (y-1)(2y-1)
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