Find:
      \int \frac{dx}{\sqrt{5-4x-2x^{2}}}

 

 

 

 
 
 
 
 

Answers (1)

I= \int \frac{dx}{\sqrt{5-4x-2x^{2}}}
   I= \frac{1}{\sqrt{2}}\int \frac{dx}{\sqrt{-\left ( x^{2}+2x-\frac{5}{2} \right )}}= \frac{1}{\sqrt{2}}\int \frac{dx}{\sqrt{-\left ( x^{2}+2x+1^{2}-\frac{5}{2}-1 \right )}}
       I= \frac{1}{\sqrt{2}}\int \frac{dx}{\sqrt{\left ( \sqrt{\frac{7}{2}} \right )^{2}-\left ( x+1 \right )^{2}}}= \frac{1}{\sqrt{2}}\sin^{-1}\frac{x+1}{\sqrt{\frac{7}{2}}}
or \frac{1}{\sqrt{2}}\sin^{-1}\left ( \frac{\sqrt{2}\left ( x+1 \right )}{\sqrt{7}} \right )+c

Preparation Products

Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
Buy Now
Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
Buy Now
Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
Buy Now
Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Boost your Preparation for JEE Main with our Foundation Course
 
Exams
Articles
Questions