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  • Find a point on x axis whch is equidistant from A(2,-5) and B(-2, 9)

Find a point on x axis whch is equidistant from A(2,-5) and B(-2, 9)

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Solution: we know that a point on x axis is of the form (x,0).So let P(x,0) be the point equidistant from A(2,-5) and B(-2,9) Then, 

PA=PB

\sqrt(x-2)^2+(0+5)^2=sqrt(x+2)^2+(0-9)^2\ \Rightarrow (x-2)^2+25=(x+2)^2+81\ \Rightarrow x^2-4x+4+25=x^2+4x+4+81\ \Rightarrow -8x=56\ \Rightarrow x=-7

Posted by

Deependra Verma

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