Find \left | AB \right | if A= \begin{bmatrix} 0 &-1 \\ 0& 2 \end{bmatrix}  and B= \begin{bmatrix} 3 &5 \\ 0& 0 \end{bmatrix}

 

 

 

 
 
 
 
 

Answers (1)

givenA= \begin{bmatrix} 0 & -1\\ 0& 2 \end{bmatrix} and\: B= \begin{bmatrix} 3& 5\\ 0& 0 \end{bmatrix}
Then
AB= \begin{bmatrix} 0 & -1\\ 0& 2 \end{bmatrix} \begin{bmatrix} 3& 5\\ 0& 0 \end{bmatrix}
         = \begin{bmatrix} 0 & 0\\ 0& 0\end{bmatrix}
\therefore \left | AB \right |= \begin{bmatrix} 0 & 0\\ 0& 0 \end{bmatrix}= 0

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