# Find the amount of heat required to change 10g of ice at -5c to water at 20c.

m=10g

Specific heat of ice= 0.5

Latent heat of fusion from ice to water L= 80cal

Specific heat of water=1

Latent heat of vaporization L= 540cal

### Case 1

Heat required to convert ice at −5oC to 0oC
Q1?=mSΔT          Q1?=10×0.5×5       Q1?=25cal

Case 2
Heat required to convert ice into water at 0oC
Q2?=mL     Q2?=10×80
Q2?=800cal

Case 3
Heat required to convert water from 0oC to 100oC
Q3?=mSΔT       Q3?=10×1×100
Q3?=1000cal

Case 4
Heat required to convert water into steam at 100oC
Q4?=mL           Q4?=10×540
Q4?=5400cal

Total heat required Qtotal?=Q1?+Q2?+Q3?+Q4?

Qtotal?=25+800+1000+5400

Qtotal?=7225cal

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