Find the angle between two vector a and Vector b with magnitude 2 and 1 respectively , and such that vector a . vector b =square root 3

Answers (1)

Solution:   we have ,

                   veca cdot vecb=sqrt3,left | veca 
ight |=2 and  left | vecb 
ight |=1

            Let   	heta   be the angle  between  veca  and  vecb. Then ,

          Rightarrow           cos 	heta=fracveca cdot vecbleft | veca 
ight |left | vecb 
ight |=fracsqrt32

        Rightarrow                 	heta=fracpi6.

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