Find the cartesian equation of the line which passes through the point \left ( -2,4,-5 \right ) and is parallel to the line  \frac{x+3}{3}= \frac{4-y}{5}= \frac{z+8}{6}

 

 

 

 
 
 
 
 

Answers (1)

Given: hence \frac{x+3}{3}= \frac{4-y}{5}= \frac{z+8}{6}  passing through point \left ( -2,4,-5 \right )
As there 2 lines are parallel, their direction ratios will be equal ratios
Equation of the given line is
\frac{x+3}{3}= \frac{4-y}{5}= \frac{z+8}{6}
\Rightarrow \frac{x+2}{3}= \frac{y-4}{-5}= \frac{z+5}{6}
or \Rightarrow \frac{x+2}{3}= \frac{4-y}{5}= \frac{z+5}{6}  which is the required equation.

 

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