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Find the definite integral 2(x)(1+sinx)/1+cos^2 x (where lower limit -pi and upper limit pi)

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Solution:  We have ,

                  I=int_-pi^pifrac(2x)(1+sin x)1+cos^2xdx

    \ \ Rightarrow I=int_-pi^pifrac2x1+cos^2xdx+int_-pi^pifrac2xsin x1+cos^2xdx\ \ I= 4int _0^pifracxsin x1+cos^2xdx

ecause            frac2x1+cos^2x    is odd   and   fracxsin x1+cos^2x  is even 

Apply        int _0^2af(x)dx=2int _0^af(x)dx     Put   cos x=t

Hence ,          I=pi^2

 

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Deependra Verma

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