# Find the distance between the parallel planes and

Given Planes:

$2x + y + 2z = 8 \Rightarrow 4x+2y+4z=16$

$4x + 2y + 4z = -5$

Distance between two parallel planes:

$d=\frac{\left|d_{1}-d_{2}\right|}{\sqrt{a^{2}+b^{2}+c^{2}}}$

$d=\frac{\left|16-(-5)\right|}{\sqrt{4^{2}+2^{2}+4^{2}}}$

$d=\frac{21}{\sqrt{36}} = \frac{21}{6}$

$d= \frac{7}{2} \ units$

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