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Find the largest number that will divide 2053 and 967 and leaves a remainder of 5 and 7 respectively.

Answers (1)

let the number be x.

Now if it leaves a remainder 5 when 2053 is divided by it then 2048(2053-5) is divisible by it.

Similarly 960(967-7) is also divisible by it.

HCF of 2048 and 960=64

Therefore, the largest number which divides 2053 and 967 and leaves  remainder  5 and 7 respectively is 64.

Posted by

shubham.krishnan

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