Find the largest number that will divide 398, 436 and 542 leaving remainders 7,11 and 15

Answers (1)
S safeer

398-7=391
436-11=425
542-15=527

HCF of 391, 425 and 527 is the largest number that will divide 398, 436 and 542 leaving remainders 7,11 and 15

391=17 x 23
436-11=425=17 x 25
542-15=527=17x 31

HCF is 17

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