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Find the value of 5 sec^2 A- 5 tan ^2 A

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5\sec^2A-5 \tan ^2A = 5(\sec^2A- \tan ^2A) .............(i)

We know  \sec^2\theta -\tan^2\thea = 1
Therefore, equation (i) becomes, 5\times 1 = 5

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Ravindra Pindel

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