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Find the value of the polynomial p(z)= 3z^3-4z+root 17 when z=3

Answers (1)

p(z)= 3z³-4z+√17

when z=3 => p(3) = 3(3)³-4x3+√17

= 81 - 12 +√17

= 69 + √17

Posted by

Ravindra Pindel

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