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  • Find the value of x if i-) 21:27::3.5:x ii-)10/3:x::5/2:5/4

Find the value of x if i-) 21:27::3.5:x ii-)10/3:x::5/2:5/4

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i-) Using cross product rule,we get
    21 imes x=27 imes3.5           (Product of means=Product of extremes)
 Rightarrow x=frac27 imes3.521=frac9 imes3.57=9 imes0.5=4.5
ii-) Given 
   frac103:x=frac52:frac54
  Using cross product rule,we get       (Product of means=Product of extremes)
  x imesfrac52=frac103 imesfrac54
  x=frac103 imesfrac54 imesfrac25=frac53=1 frac23

Posted by

Deependra Verma

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